Class 7 chapter 9 Exercise 9C

 Exercise 9C 

Question 1 

A shopkeeper bought a second hand car for Rs 1,50,000. He spent Rs, 10,000 on its painting and repair and then sold it far Rs, 200,000. Find his profit or loss. 

Sol: Cast price = Rs ,1,50,000
Spent on painting repair= Rs 10,000
Effective,  C.P = $1,50,000+10,000=Rs 1,60,000$
Selling price S.P = Rs 2,00,000
S.P > C.P = Profit = 200000- 1,60000
= Rs 40,000 Answer profit 

Question 2

Vinay bought a house for Rs 4,50,000. HE Spent Rs.20,000 on repairs and white washing and then sold it for Rs 4,30,000. Find his gain\loss

Sol: C.P OF HOUSE =RS 4,50,000
spent on Repair $=220,000$
E.C.P = Rs 4,50,00+ Rs 20,000= Rs 4,70,000

S.p = Rs 4,30,000
C.P >S.P =loss= $4,70,000-4,30,000$
40,000 loss

Question 3

A dealer bought 50 quintals of rice at the rate of Rs 800 per quintal. He paid Rs 400 charges and Rs 600 as transportation charges . Then he sold the whole stack at Rs 750 per quintal . find his gain or loss. 

Sol: C.P of per rice = Rs 800 
Charge spent = 400+ 600= Rs 1000

C.p of 50 quintal of rice = $50 \times 800$
=40,000

E.C.P = Rs $40,000+1000=Rs 41,000$
S.P = $750 \times 50=Rs 37500$

C.P >S.P  = loss= $41,000-37500$
= Rs 3500 loss

Question 4

Find the gain or loss % in the following : 

(i) C.P = Rs 750

Sol: Expenses = Rs 50 
E.C.P = 750 + 50 = 800
Profit = Rs 80

Profit % = $\frac{\text { Profit}}{C.P} \times 100$
$\frac{80}{800} \times 100$ 
= 10% 

(ii) C.P = Rs 5200
S.P = Rs 5070

C.P >S.P 
Loss = 5200- 5070 
=Rs 130

Loss % = $\frac{130}{5200} \times 100$
= 2.5% 

(iii) $C \cdot p=Rs 400$
S.P. $=₹ 460$

Profit = 460 - 40= Rs 60
Profit =$=\frac{60}{400} \times 100$
$=15$

(iv) C.P = Rs 50 
S.P = Rs 42
Loss = 50 - 42= Rs 8
Loss =8 

(v)C.P = Rs 4,6000; Over heads = 4000

E.C.P = Rs 50,000
S.P = Rs 60,000
Gain\loss %= ? 
S.P > C.P

Question 5

Find the S.P when 

(i) C.P = Rs 20
Sol: Gain = 10% 
Gain = 10% of 20 = $\frac{10}{100} \times 20$ = Rs 2 

S.P = C.P + Gain = 20+2= Rs 22

(ii) C.P = Rs 12.50 ; Loss = $13 \frac{1}{3} \%=\frac{40}{3} \%$

Sol: Loss = $\frac{40}{3} \% of  \quad 12.50$
= $\frac{40}{3 \times 100}$ $times \frac{+2.50}{100}$ =  $\frac{5}{3}=Rs 1.67$

S.P = C.P - Loss = Rs 12.50 - 1.67
= Rs 10.82 

Question 6

Find the C.P when, 

(i) S.P= Rs 12 ; Gain = 20% 
Let C.P = x
Gain = 20% of x = $\frac{20}{100} \times 21=\frac{x}{5}$
S.P= $x+\frac{x}{5}=\frac{5 x+4}{5}=\frac{6 x}{5}=12$
= x=  $12 \times \frac{5}{6}=Rs 10$

(ii) S.P = Rs 360 ; Loss 10% 
Loss = 10% of x = $\frac{10}{100} \times x=\frac{x}{10}$
 S.P $=x-\frac{x}{10}=\frac{10 x-x}{10}=\frac{9 x}{10}$
$\Rightarrow \quad \frac{9 x}{10}=360$
$\Rightarrow x=\frac{360}{9} \times 10=Rs 400$

Question 7

By Selling a motor cycle for Rs 23000 a dealer gains 15% .Find its C.P 

Sol: Let C.P =  x   Given S.P = Rs 23,000
Gain = 15 % of x = $\frac{18}{100} \times 21$= $\frac{3x}{20}$
S.P = $2 x+\frac{3 x}{20}=\frac{20 x+3 x}{20}=\frac{23 x}{20}$

∵ $\frac{23 x}{20}=23000 \Rightarrow x$ = $23000 \times \frac{20}{23}$
C.P (x) = Rs 20,000

Question 8

The C.P of an article is Rs 6250 . Sudhir sells it at a loss of 24% . Find its S.P.

Sol: C.P = Rs 6250
Loss = 24% of 6250

$\frac{24}{100} \times 6,250$ = Rs 1500

S.P = C.P - loss
$=6250-1500$ 
S.P = Rs 4750 Answer 


No comments:

Post a Comment

Contact form

Name

Email *

Message *